y^2+12y-160=0

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Solution for y^2+12y-160=0 equation:


Simplifying
y2 + 12y + -160 = 0

Reorder the terms:
-160 + 12y + y2 = 0

Solving
-160 + 12y + y2 = 0

Solving for variable 'y'.

Factor a trinomial.
(-20 + -1y)(8 + -1y) = 0

Subproblem 1

Set the factor '(-20 + -1y)' equal to zero and attempt to solve: Simplifying -20 + -1y = 0 Solving -20 + -1y = 0 Move all terms containing y to the left, all other terms to the right. Add '20' to each side of the equation. -20 + 20 + -1y = 0 + 20 Combine like terms: -20 + 20 = 0 0 + -1y = 0 + 20 -1y = 0 + 20 Combine like terms: 0 + 20 = 20 -1y = 20 Divide each side by '-1'. y = -20 Simplifying y = -20

Subproblem 2

Set the factor '(8 + -1y)' equal to zero and attempt to solve: Simplifying 8 + -1y = 0 Solving 8 + -1y = 0 Move all terms containing y to the left, all other terms to the right. Add '-8' to each side of the equation. 8 + -8 + -1y = 0 + -8 Combine like terms: 8 + -8 = 0 0 + -1y = 0 + -8 -1y = 0 + -8 Combine like terms: 0 + -8 = -8 -1y = -8 Divide each side by '-1'. y = 8 Simplifying y = 8

Solution

y = {-20, 8}

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